DAT Review · General Chemistry

Buffers and Titrations

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On this page 7 sections
  1. In 30 seconds
  2. The college version
  3. Eli explains
  4. Key takeaway
  5. Check yourself
  6. Study tools
  7. Sources & references

In 30 seconds

Buffers and titrations are high-priority DAT topics — expect 3–5 questions, often integrated with acid-base equilibrium. You must know the Henderson-Hasselbalch equation, how to identify buffer systems, the shape of titration curves for each acid-base combination, and the significance of the half-equivalence point. Equivalence point pH is a common discriminator: strong-strong = 7, weak acid-strong base > 7, weak base-strong acid < 7.

The college version

Core Review

Buffers

A buffer solution resists changes in pH upon addition of small amounts of acid or base. A buffer consists of either:

  • A weak acid + its conjugate base (e.g., CH₃COOH / CH₃COO⁻)
  • A weak base + its conjugate acid (e.g., NH₃ / NH₄⁺)

When acid (H⁺) is added, the conjugate base neutralizes it: A⁻ + H⁺ → HA. When base (OH⁻) is added, the weak acid neutralizes it: HA + OH⁻ → A⁻ + H₂O. In both cases, the pH changes only slightly.

Henderson-Hasselbalch Equation:

pH = pK_a + log([A⁻] / [HA])

For a base buffer: pOH = pK_b + log([BH⁺] / [B]).

This equation tells you the pH of a buffer given the ratio of conjugate base to acid. When [A⁻] = [HA], pH = pK_a — this is the half-equivalence point, where the buffer is most effective.

Buffer capacity is the amount of acid or base a buffer can neutralize before significant pH change. Capacity is highest when:

  • The concentrations of buffer components are high.
  • [A⁻] / [HA] is close to 1 (pH ≈ pK_a).

Effective buffer range: pH = pK_a ± 1. Outside this range, the buffer has minimal capacity.

Worked Example: A buffer contains 0.50 M CH₃COOH (pK_a = 4.74) and 0.75 M CH₃COONa. What is the pH?

  • pH = 4.74 + log(0.75 / 0.50) = 4.74 + log(1.5) = 4.74 + 0.18 = 4.92

Titrations

A titration is the gradual addition of a titrant of known concentration to an analyte of unknown concentration until complete reaction. The equivalence point is when stoichiometrically equivalent amounts of acid and base have reacted. The endpoint is the observable signal (color change of indicator) that approximates the equivalence point.

Strong Acid + Strong Base (e.g., HCl + NaOH):

  • Equivalence point pH = 7.00 (neutral salt, no hydrolysis).
  • Curve: flat initial region, sharp vertical jump at equivalence.
  • Indicator: phenolphthalein (colorless → pink, pH 8.2–10.0) or bromothymol blue (6.0–7.6).

Weak Acid + Strong Base (e.g., CH₃COOH + NaOH):

  • Initial pH > strong acid (weak acid is partially dissociated).
  • Buffer region before equivalence (resists pH change).
  • Half-equivalence point: pH = pK_a (buffer components are equal).
  • Equivalence point pH > 7 (conjugate base CH₃COO⁻ hydrolyzes to produce OH⁻).
  • Indicator: phenolphthalein (pH 8.2–10.0).

Weak Base + Strong Acid (e.g., NH₃ + HCl):

  • Equivalence point pH < 7 (conjugate acid NH₄⁺ hydrolyzes to produce H⁺).
  • Indicator: methyl red (pH 4.4–6.2) or bromocresol green (3.8–5.4).

Key features of a weak acid-strong base titration curve:

  1. Initial gradual rise (weak acid buffer region).
  2. Steepest slope at the half-equivalence point (maximum buffering).
  3. Vertical jump through the equivalence point.
  4. pH at equivalence = determined by conjugate base hydrolysis.
  5. After equivalence, pH levels off as excess strong base dominates.

Indicator Selection

An indicator is itself a weak acid (HIn ⇌ H⁺ + In⁻) with different colors for HIn and In⁻. Color change occurs over pH = pK_a(In) ± 1. Choose an indicator whose pK_a is close to the equivalence point pH.

Titration TypeEquivalence pHSuitable Indicator
Strong acid + strong base7Bromothymol blue, phenolphthalein
Weak acid + strong base> 7Phenolphthalein
Weak base + strong acid< 7Methyl red, bromocresol green

Polyprotic Acid Titrations

Polyprotic acids (H₂A, H₃A) titrate in steps. Each acidic proton has its own equivalence point and buffer region. H₂CO₃ has two equivalence points; H₃PO₄ has three. Each half-equivalence point corresponds to pH = pK_a for that proton.

Key Equations

EquationMeaning
pH = pK_a + log([A⁻]/[HA])Henderson-Hasselbalch
[A⁻] = [HA] → pH = pK_aHalf-equivalence point
M_acid × V_acid = M_base × V_baseEquivalence point (monoprotic)
Buffer range: pH = pK_a ± 1Effective buffering zone

Common Traps

  • Thinking HCl + NaCl is a buffer (it's not — HCl is a strong acid).
  • Forgetting that at the equivalence point, you have only the salt — use hydrolysis to find pH.
  • Confusing equivalence point (stoichiometric) with endpoint (indicator change).
  • Using concentration instead of moles at equivalence: M_acid × V_acid = M_base × V_base works only for 1:1 stoichiometry.
  • Assuming all titration curves have pH = 7 at equivalence.
Eli, the EliExplains learning guide

Eli explains

The same idea, in plain words

Explain it like I’m 10

A buffer is like a sponge that soaks up extra acid or base without letting the pH change much. The sponge is a team of a weak acid and its partner (conjugate base). A titration is like slowly pouring one liquid into another until they perfectly cancel each other out — that perfect moment is the equivalence point. The half-equivalence point is when you're halfway there: equal amounts of acid and its partner are present, and the pH equals a special number (pK_a) that identifies the acid.

Key takeaways

  • Buffer composition: MUST be weak acid + conjugate base (or weak base + conjugate acid). Strong acid + its salt is NOT a buffer.
  • At half-equivalence, pH = pK_a. This is the most heavily tested titration fact.
  • Equivalence point pH reflects salt hydrolysis: weak acid + strong base → basic equivalence point.
  • The vertical region of a titration curve is where the indicator must change color.
  • Adding water to a buffer changes concentrations equally — the ratio [A⁻]/[HA] stays the same, so pH does not change (but buffer capacity decreases).

Check yourself

3 review questions from the chapter. Try each one, then open the answer.

  1. A buffer is made from 0.20 M NH₃ (K_b = 1.8 × 10⁻⁵) and 0.30 M NH₄Cl. What is the pH?

    Show answer

    pK_a(NH₄⁺) = 14.00 − pK_b = 14.00 − (−log(1.8 × 10⁻⁵)) = 14.00 − 4.74 = 9.26. pH = 9.26 + log(0.20/0.30) = 9.26 + log(0.667) = 9.26 − 0.176 = 9.08.

  2. 25.0 mL of 0.100 M HNO₃ is titrated with 0.100 M NaOH. What volume of NaOH is needed to reach the equivalence point, and what is the pH?

    Show answer

    V_base = (0.100 × 25.0) / 0.100 = 25.0 mL. Strong acid + strong base → pH = 7.00 at equivalence.

  3. A weak acid (pK_a = 5.00) is titrated with NaOH. What is the pH after adding half the volume needed to reach equivalence?

    Show answer

    At the half-equivalence point, [HA] = [A⁻], so pH = pK_a = 5.00.

Keep learning

Ready to build on this? Continue to the next lesson.

Study tools & related lessonsYou’ll learn to · Related

You’ll learn to

  • Define a buffer and identify buffer systems from component lists.
  • Apply the Henderson-Hasselbalch equation to calculate buffer pH.
  • Explain buffer capacity and the conditions under which a buffer is most effective.
  • Sketch and interpret titration curves for strong acid-strong base, weak acid-strong base, and weak base-strong acid.
  • Locate equivalence points and half-equivalence points on a titration curve.
  • Select an appropriate indicator for a given titration.

Sources & references

  1. OpenStax Chemistry 2e, Chapter 14: Acid-Base Equilibria (Buffers), Chapter 15: Equilibria of Other Reaction Classes.
  2. Chemistry LibreTexts: Buffers and Titrations.
  3. NIST: Buffer standards.

This lesson was adapted from the open educational references above; their licenses and attributions are preserved. See Copyright & Licensing.

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