General Chemistry II · Acid Base Equilibria

Hydrolysis of Salts: Acidic, Basic, and Neutral Solutions

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On this page 8 sections
  1. In 30 seconds
  2. Why this matters
  3. The college version
  4. Eli explains
  5. Worked example
  6. Key takeaway
  7. Study tools
  8. Sources & references

In 30 seconds

When a salt dissolves, its ions may react with water in a process called hydrolysis (literally "water-splitting"). Whether the resulting solution is acidic, basic, or neutral is decided by the ions' parent acid and base. The rule of thumb: the cation of a strong base and the anion of a strong acid are spectators (neutral solution); the cation of a weak base (or a small, highly charged metal ion) makes the solution acidic; and the anion of a weak acid makes it basic.

Why this matters

Salt hydrolysis explains the everyday pH of household and biological solutions: why baking soda (NaHCO₃) and soap (sodium salts of fatty acids) feel slippery and basic, why ammonium fertilizers acidify soil, and why many metal salts (alum, ferric chloride) are acidic in water — a fact used in water treatment and antiperspirants. It is also the key to understanding how buffers resist pH change.

The college version

Core Concept

When a salt dissolves, its ions may react with water in a process called hydrolysis (literally "water-splitting"). Whether the resulting solution is acidic, basic, or neutral is decided by the ions' parent acid and base. The rule of thumb: the cation of a strong base and the anion of a strong acid are spectators (neutral solution); the cation of a weak base (or a small, highly charged metal ion) makes the solution acidic; and the anion of a weak acid makes it basic.

Key Ideas

  • Neutral: strong acid + strong base → neither ion hydrolyzes (NaCl, KNO₃, CaCl₂).
  • Acidic: strong acid + weak base → the cation hydrolyzes (NH₄Cl → NH₄⁺ donates H⁺).
  • Basic: weak acid + strong base → the anion hydrolyzes (NaCH₃COO → CH₃COO⁻ accepts H⁺).
  • Both hydrolyze: weak acid + weak base → compare Ka of the cation to Kb of the anion (NH₄CH₃COO ≈ neutral; NH₄CN is basic).
  • Metal-cation acidity: small, highly charged cations (Fe³⁺, Al³⁺, Cu²⁺) polarize water and release H⁺, giving acidic solutions even without a proton to donate.

Equations and Variables

  • Acidic cation: NH₄⁺ + H₂O ⇌ H₃O⁺ + NH₃, Ka = Kw/Kb(NH₃)
  • Basic anion: CH₃COO⁻ + H₂O ⇌ CH₃COOH + OH⁻, Kb = Kw/Ka(CH₃COOH)
  • Metal ion: [Fe(H₂O)₆]³⁺ + H₂O ⇌ [Fe(H₂O)₅OH]²⁺ + H₃O⁺
  • For an acidic salt: [H₃O⁺] = √(Ka × C_salt)
  • For a basic salt: [OH⁻] = √(Kb × C_salt)

How It Works

  1. Split the salt into its ions and identify the "parent" acid and base that would form each ion.
  2. The conjugate of a strong acid (e.g., Cl⁻) or strong base (e.g., Na⁺) is too weak to hydrolyze — it is a spectator.
  3. The conjugate of a weak acid (CH₃COO⁻) hydrolyzes as a base; the conjugate of a weak base (NH₄⁺) hydrolyzes as an acid.
  4. Convert the needed Ka or Kb using Ka × Kb = Kw.
  5. Solve with an ICE table to get [H₃O⁺] or [OH⁻], then the pH.
  6. When both ions hydrolyze, compare their Ka and Kb to decide the net direction.

Worked Example

Predict whether each solution is acidic, basic, or neutral, and find the pH of 0.10 M NaF (Ka of HF = 6.8 × 10⁻⁴).

  • NaCl: Na⁺ (from NaOH, strong) and Cl⁻ (from HCl, strong) → neutral.
  • NH₄Cl: Cl⁻ spectator; NH₄⁺ (from weak NH₃) → acidic.
  • NaF: Na⁺ spectator; F⁻ is the conjugate base of weak HF → basic.

For 0.10 M NaF:

Kb(F⁻) = Kw / Ka(HF) = (1.0 × 10⁻¹⁴) / (6.8 × 10⁻⁴) = 1.47 × 10⁻¹¹

F⁻ + H₂O ⇌ HF + OH⁻; Kb = x²/(0.10 − x) ≈ x²/0.10

x = [OH⁻] = √(1.47 × 10⁻¹¹ × 0.10) = √(1.47 × 10⁻¹²) = 1.21 × 10⁻⁶ M

pOH = 5.92 → pH = 14.00 − 5.92 = 8.08 (basic) ✓

How it works

  1. Split the salt into its ions and identify the "parent" acid and base that would form each ion.
  2. The conjugate of a strong acid (e.g., Cl⁻) or strong base (e.g., Na⁺) is too weak to hydrolyze — it is a spectator.
  3. The conjugate of a weak acid (CH₃COO⁻) hydrolyzes as a base; the conjugate of a weak base (NH₄⁺) hydrolyzes as an acid.
  4. Convert the needed Ka or Kb using Ka × Kb = Kw.
  5. Solve with an ICE table to get [H₃O⁺] or [OH⁻], then the pH.
  6. When both ions hydrolyze, compare their Ka and Kb to decide the net direction.

Common confusions

  • "All salts are neutral." — Only strong-acid/strong-base salts are; many common salts are acidic or basic.
  • "Na⁺ or Cl⁻ hydrolyzes." — They are spectators; they are conjugates of a strong base/acid and are too weak to react.
  • "NH₄Cl is basic because NH₃ is a base." — NH₄⁺ is the acid form of ammonia; it donates a proton and makes the solution acidic.
  • "Metal ions with no H can't be acidic." — Small, highly charged cations (Fe³⁺, Al³⁺) release H⁺ from coordinated water molecules.
  • "You can skip the Kw conversion." — For salt pH you must convert the weak parent's Ka to the ion's Kb (or vice versa) with Ka × Kb = Kw.

Quick review

  • Neutral: strong acid + strong base.
  • Acidic: strong acid + weak base (cation hydrolyzes).
  • Basic: weak acid + strong base (anion hydrolyzes).
  • Use Ka × Kb = Kw to convert constants for the hydrolyzing ion.
  • Metal cations Fe³⁺, Al³⁺, Cu²⁺ → acidic via water polarization.
Eli, the EliExplains learning guide

Eli explains

The same idea, in plain words

Explain it like I’m 10

Dissolving a salt is like inviting two houseguests over — one from an "acid family" and one from a "base family." If both come from strong families, they're polite and leave the water alone (neutral). If the acid-family guest comes from a weak family, they start grabbing protons and make things basic; if the base-family guest is weak, they hand out protons and make things acidic. (The analogy omits the metal-ion case, where the guest isn't "from a weak family" but just a small, needy ion that bullies water into giving up a proton.)

Worked example

Worked Example

Predict whether each solution is acidic, basic, or neutral, and find the pH of 0.10 M NaF (Ka of HF = 6.8 × 10⁻⁴).

  • NaCl: Na⁺ (from NaOH, strong) and Cl⁻ (from HCl, strong) → neutral.
  • NH₄Cl: Cl⁻ spectator; NH₄⁺ (from weak NH₃) → acidic.
  • NaF: Na⁺ spectator; F⁻ is the conjugate base of weak HF → basic.

For 0.10 M NaF:

Kb(F⁻) = Kw / Ka(HF) = (1.0 × 10⁻¹⁴) / (6.8 × 10⁻⁴) = 1.47 × 10⁻¹¹

F⁻ + H₂O ⇌ HF + OH⁻; Kb = x²/(0.10 − x) ≈ x²/0.10

x = [OH⁻] = √(1.47 × 10⁻¹¹ × 0.10) = √(1.47 × 10⁻¹²) = 1.21 × 10⁻⁶ M

pOH = 5.92 → pH = 14.00 − 5.92 = 8.08 (basic) ✓

Key takeaways

  • ### High-Yield Facts
  • Strong acid + strong base salt → neutral (spectator ions only).
  • Strong acid + weak base salt → acidic (cation hydrolyzes).
  • Weak acid + strong base salt → basic (anion hydrolyzes).
  • Weak acid + weak base salt → compare Ka(cation) vs Kb(anion).
  • Conjugate of a strong acid/base never hydrolyzes appreciably.
  • Fe³⁺, Al³⁺, Cu²⁺ give acidic solutions by polarizing water.

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You’ll learn to

  • Predict whether a salt solution is acidic, basic, or neutral.
  • Write the hydrolysis reaction of an acidic or basic ion.
  • Calculate the pH of a salt solution using Ka or Kb.
  • Relate salt behavior to the strength of the parent acid and base.

Sources & references

  1. OpenStax, *Chemistry 2e*, "14.4 Hydrolysis of Salts." https://openstax.org/books/chemistry-2e/pages/14-4-hydrolysis-of-salts
  2. OpenStax, *Chemistry 2e*, "14.3 Relative Strengths of Acids and Bases." https://openstax.org/books/chemistry-2e/pages/14-3-relative-strengths-of-acids-and-bases
  3. PubChem, "Sodium Acetate." https://pubchem.ncbi.nlm.nih.gov/compound/Sodium-acetate
  4. Chem LibreTexts, "Chemistry 2e (OpenStax) — 14: Acid-Base Equilibria." https://chem.libretexts.org/Bookshelves/General_Chemistry/Chemistry_2e_%28OpenStax%29/14%3A_Acid-Base_Equilibria

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