Organic Chemistry · Alcohols and Phenols
Reactions of Phenols
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In 30 seconds
Phenols react at two distinct sites: at the oxygen (after deprotonation to phenoxide, a powerful nucleophile) and at the ring (an activated aromatic system that undergoes electrophilic substitution easily). The oxygen chemistry gives ethers and esters — including the reaction that makes aspirin. The ring chemistry gives halogenated, nitrated, and carboxylated phenols — including the industrial route to salicylic acid (Kolbe–Schmitt). Phenols are also easily oxidized to quinones, a reaction with deep biological importance.
A useful mental map: (1) O–H reactivity — deprotonation, Williamson ether synthesis SN2 alkylation of an alkoxide/phenoxide by an alkyl halide Full entry →, esterification Reaction of an alcohol/phenol with an acid chloride or anhydride Full entry →; (2) ring reactivity — electrophilic aromatic substitution (EAS) Replacing an aromatic H with an electrophile Full entry → at ortho/para; (3) oxidation — phenols ↔ quinones.
Why this matters
The reactions of phenols power several billion-dollar industries and central biological processes:
- Aspirin is made by acetylating the phenolic –OH of salicylic acid — the most famous pharmaceutical reaction.
- Aryl ethers made from phenoxides appear in drugs, fragrances, and polymers.
- Kolbe–Schmitt carboxylation is the industrial route to salicylic acid, the aspirin precursor.
- quinone Cyclic dione from oxidation of a hydroquinone Full entry →/hydroquinone redox couples power electron transport in mitochondria (coenzyme Q) and photosynthesis; vitamin K's blood-clotting function is quinone-based.
- Phenol's easy bromination (no catalyst needed) is a classic demonstration of ring activation — a favorite exam topic.
The college version
Core Concepts
Deprotonation: making the phenoxide nucleophile
Phenol (pKa ≈ 10) is deprotonated by NaOH or NaH to give the phenoxide ion Conjugate base of phenol (C₆H₅O⁻) Full entry →:
C6H5OH + NaOH ⟶ C6H5O-Na+ + H2O
The phenoxide is a far better nucleophile than phenol itself (negative charge on oxygen, delocalized but available). Bicarbonate is too weak a base to do this (see Topic 9).
Williamson ether synthesis
Phenoxide + primary alkyl halide (or methyl/benzyl halide) → aryl alkyl ether via SN2 One-step substitution: nucleophile attacks as leaving group departs Full entry →:
C6H5O- + CH3I ⟶ C6H5OCH3 + I-
Anisole (methoxybenzene) is made this way. Mechanism: the phenoxide oxygen attacks the back side of the carbon bearing the leaving group; the halide leaves; the C–O bond forms with inversion at carbon. Requirements: a good leaving group and an unhindered carbon — methyl and primary halides work well, secondary poorly, tertiary halides give elimination instead. Aryl halides (e.g., bromobenzene) cannot be used — SN2 does not occur at aromatic carbons, which is why you cannot make diphenyl ether by direct Williamson reaction.
Esterification: the aspirin reaction
Phenols react with acid chlorides or anhydrides (with pyridine or NaOH as base) to give phenyl esters:
C6H5OH + CH3COCl ⟶ C6H5OCOCH3 + HCl
Salicylic acid (o-hydroxybenzoic acid) has both a phenolic –OH and a –COOH. Acetylation with acetic anhydride converts only the phenolic –OH to an ester, giving acetylsalicylic acid Aspirin: salicylic acid with the phenolic –OH acetylated Full entry → — aspirin:
HOC6H4COOH + (CH3CO)2O ⟶ CH3COOC6H4COOH + CH3COOH
The –COOH is left free, which is essential because aspirin's anti-inflammatory activity depends on it.
Electrophilic aromatic substitution: the activated ring
The –OH group is a strong ortho/para director and ring activator. Phenol reacts with Br₂ in water even without a Lewis acid catalyst — three bromines add rapidly to give 2,4,6-tribromophenol Triple bromination product of phenol Full entry → (a white solid):
C6H5OH + 3Br2 ⟶ Br3C6H2OH + 3HBr
Nitration with dilute nitric acid gives mostly p-nitrophenol (plus the ortho isomer); the isomers separate by steam distillation because the ortho isomer hydrogen-bonds intramolecularly and is more volatile. Compare with benzene, which needs fuming nitric acid, sulfuric acid, and heat — the –OH makes the ring dramatically more reactive.
Kolbe–Schmitt carboxylation
Heating sodium phenoxide with CO₂ under pressure, then acidifying, gives salicylic acid (ortho carboxylation):
C6H5O-Na+ + CO2 125 °C, pressure⟶ NaOOC–C6H4OH H3O+⟶ HOOC–C6H4OH
The phenoxide attacks the electrophilic carbon of CO₂, and the carboxylate lands ortho to the –OH. This is the industrial synthesis of salicylic acid.
Oxidation: phenols and quinones
Phenols are easily oxidized (they darken in air). With appropriate oxidants (e.g., Ag₂O, Na₂Cr₂O₇), hydroquinones give quinones:
HOC6H4OH [O]⟶ O=C6H4=O + 2H+ + 2e-
The hydroquinone/quinone pair is a reversible two-electron redox couple — the basis of coenzyme Q in the electron transport chain and of vitamin K's role in blood clotting. Hydroquinone and derivatives are also used as photographic developers and radical scavengers.
How It Works / Step-by-Step Process
Making an aryl alkyl ether (Williamson, general procedure):
- Deprotonate the phenol: C₆H₅OH + NaOH → C₆H₅O⁻Na⁺ (in water/ethanol), or use NaH in an aprotic solvent.
- Add the alkyl halide (methyl, primary, or benzyl — never tertiary): C₆H₅O⁻ attacks the carbon back side, halide leaves (SN2).
- Isolate: pour into water, extract with organic solvent, dry, remove solvent.
- Verify by spectroscopy: anisole shows aryl C–O (~1240 cm⁻¹ in IR) and a 3H singlet at ~3.8 ppm (OCH₃) in ¹H NMR.
Aspirin synthesis (educational outline, not a procedure to run without supervision):
- Warm salicylic acid with acetic anhydride and a catalytic amount of acid (e.g., phosphoric acid).
- The phenolic –OH is acetylated; the –COOH is not.
- Pour into cold water — aspirin precipitates; wash, recrystallize, dry.
- A negative FeCl₃ test Iron(III) chloride color test for phenols/enols Full entry → confirms no free phenol remains.
Common Confusions
| Do not confuse | With | Difference |
|---|---|---|
| Williamson on phenols | Alkylation of the ring | The phenoxide oxygen alkylates (SN2, gives ethers); ring alkylation needs Friedel–Crafts-type conditions |
| Aryl halides in Williamson | Alkyl halides | Ar–X cannot do SN2 (aromatic carbons don't undergo back-side attack) — diphenyl ether cannot be made this way |
| 3° alkyl halide in Williamson | Methyl/1° halides | 3° halides undergo elimination (E2) with the basic phenoxide instead of substitution — no ether forms |
| Phenol + Br₂ | Benzene + Br₂ | Phenol reacts without catalyst (activated ring) to give 2,4,6-tribromophenol; benzene needs FeBr₃ and gives mono-bromobenzene |
| Oxidation of phenols | Oxidation of alcohols | Alcohols → aldehydes/ketones/carboxylic acids; phenols → quinones (ring diones), a different redox system |
| Ester of phenol | Ester of carboxylic acid | Phenyl esters (ArO–C(=O)R) form from phenols; carboxylate esters (R–O–C(=O)R′) form from alcohols/acids — different products |
| FeCl₃ positive test | Only phenols | Enols (e.g., 1,3-dicarbonyl tautomers) also give color — confirm with NMR/IR |

Eli explains
The same idea, in plain words
Explain it like I’m 10
Phenol is a ring with an –OH handle that can "let go" of its hydrogen to become a negative ion — a grabby helper that can snap new pieces (like a methyl group or a CO₂ molecule) into place. The ring itself is also super-eager to catch bromine and other electrophiles without needing a catalyst. That's why phenol builds aspirin, antiseptics, and plastics — and why it turns into a yellow dye (quinone) when oxidized, like an apple browning in air.
Worked example
Example 1: Williamson stoichiometry — anisole from phenol
Problem: How many grams of anisole (C₆H₅OCH₃, molar mass 108.14 g/mol) can be made from 5.00 g of phenol (C₆H₅OH, molar mass 94.11 g/mol) if the yield is 85%?
Formula first: n = mM, then mproduct = n × Mproduct × yield fraction.
n(phenol) = 5.00 g94.11 g/mol = 5.31 × 10-2 mol
The reaction is 1:1 (one phenol → one anisole), so:
mtheoretical = (5.31 × 10-2 mol)(108.14 g/mol) = 5.75 g
mactual = 5.75 g × 0.85 = 4.89 g
Dimensional analysis (one chain):
5.00 g phenol × 1 mol phenol94.11 g phenol × 1 mol anisole1 mol phenol × 108.14 g anisole1 mol anisole × 0.85 = 4.89 g anisole
Example 2: Predicting bromination products
Problem: Predict the product when p-cresol (4-methylphenol) is treated with excess Br₂ in water.
Analysis: The –OH is a strong ortho/para director. In 4-methylphenol, the para position is already occupied by –CH₃, so electrophilic bromination occurs at the two ortho positions (carbons 2 and 6, equivalent by symmetry).
Answer: 2,6-dibromo-4-methylphenol. The methyl group also directs ortho/para, but the –OH dominates; the product still has an intact –OH, confirmed by the FeCl₃ test and a broad IR O–H stretch near 3200–3600 cm⁻¹.
Example 3: Acid–base separation logic with phenoxides
Problem: A mixture of phenol (pKa 10.0), p-nitrophenol (pKa 7.2), and anisole (no acidic proton) is dissolved in ether. Which compound is extracted into aqueous NaHCO₃? Into aqueous NaOH?
Analysis: NaHCO₃ (conjugate acid H₂CO₃, pKa 6.35) deprotonates only acids stronger than carbonic acid: p-nitrophenol (7.2) partially; phenol (10.0) not at all; anisole not at all. NaOH (conjugate acid H₂O, pKa 15.7) deprotonates both phenols fully. So NaOH extracts p-nitrophenol + phenol; NaHCO₃ extracts only the strongest acid (mostly); anisole stays in ether throughout.
Key takeaways
- Phenoxide (from NaOH) is the reactive nucleophile; it alkylates methyl/primary/benzyl halides (Williamson) — never aryl halides.
- Aspirin = acetylation of salicylic acid's phenolic –OH with acetic anhydride; the –COOH stays free.
- Phenol is so activated that Br₂/H₂O gives 2,4,6-tribromophenol with no catalyst; benzene needs FeBr₃ + Br₂.
- –OH directs electrophiles ortho/para; nitro groups deactivate but o/p mixtures still form.
- Kolbe–Schmitt: phenoxide + CO₂ (heat, pressure) → salicylic acid after acidification — industrial aspirin feedstock.
- Phenols oxidize to quinones; hydroquinone ⇌ quinone is a reversible redox couple (biology: coenzyme Q, vitamin K).
- FeCl₃ gives a violet color with phenols (enols too) — quick qualitative test.
- Safety principle: phenols are corrosive and can be toxic; work with gloves in a ventilated area and avoid skin contact.
Check yourself
6 review questions from the chapter. Try each one, then open the answer.
Write the two-step sequence (reagents) to convert phenol to anisole, and name the mechanism of the key step.
Show answer
(1) C₆H₅OH + NaOH → C₆H₅O⁻Na⁺; (2) C₆H₅O⁻ + CH₃I → C₆H₅OCH₃ + NaI. The key step is SN2 — phenoxide attacks methyl iodide's carbon from the back side.
Why can't you make diphenyl ether by reacting phenoxide with bromobenzene?
Show answer
Bromobenzene's aromatic carbon cannot undergo SN2: the back-side attack required would have to occur on an sp² carbon inside the ring, which is geometrically impossible and electronically unfavorable. Aryl ethers need different methods (e.g., copper-mediated coupling or SNAr with strong EWG).
Which functional group of salicylic acid is acetylated in aspirin synthesis, and why does the –COOH stay free?
Show answer
Only the phenolic –OH is acetylated (acetic anhydride). The –COOH is too unreactive toward acylation under these conditions, and keeping it free is essential for aspirin's pharmacological activity.
Explain why phenol reacts with Br₂ in water without a catalyst while benzene requires FeBr₃.
Show answer
The –OH donates electron density into the ring (resonance + induction), raising electron density at ortho/para carbons so they attack the electrophile (Br⁺) without needing a Lewis acid to generate it. Benzene's ring is far less electron-rich.
What is the Kolbe–Schmitt reaction Phenoxide + CO₂ → ortho-hydroxybenzoate → salicylic acid Full entry →, and why is it industrially important?
Show answer
Sodium phenoxide + CO₂ under heat/pressure gives the ortho-carboxylate; acidification gives salicylic acid — the industrial route to the aspirin precursor.
Give one biological example of a quinone/hydroquinone redox system.
Show answer
Coenzyme Q (ubiquinone/ubiquinol) shuttles electrons in the mitochondrial electron transport chain; vitamin K (a quinone) participates in blood-clotting factor carboxylation; hydroquinone is also used industrially as a developer/scavenger.
Study tools & related lessonsKey vocabulary · Related
Key vocabulary
- phenoxide ion
- Conjugate base of phenol (C₆H₅O⁻)
- Williamson ether synthesis
- SN2 alkylation of an alkoxide/phenoxide by an alkyl halide
- SN2
- One-step substitution: nucleophile attacks as leaving group departs
- esterification
- Reaction of an alcohol/phenol with an acid chloride or anhydride
- acetylsalicylic acid
- Aspirin: salicylic acid with the phenolic –OH acetylated
- electrophilic aromatic substitution (EAS)
- Replacing an aromatic H with an electrophile
- 2,4,6-tribromophenol
- Triple bromination product of phenol
- Kolbe–Schmitt reaction
- Phenoxide + CO₂ → ortho-hydroxybenzoate → salicylic acid
- quinone
- Cyclic dione from oxidation of a hydroquinone
- FeCl₃ test
- Iron(III) chloride color test for phenols/enols
Sources & references
This lesson was adapted from the open educational references above; their licenses and attributions are preserved. See Copyright & Licensing.
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