Organic Chemistry · Alcohols and Phenols

Reactions of Phenols

9 min read
Constants cross-checked against current references (PubChem, 2026-08): phenol pKa 9.99, molar mass 94.11 g/mol; anisole molar mass 108.14 g/mol; 4-nitrophenol pKa 7.15; H₂CO₃ pKa 6.35. Kolbe–Schmitt conditions (~125 °C, elevated CO₂ pressure) are standard textbook values.
Want it in plain words first? Jump to Eli explains — the same idea, no jargon.
On this page 9 sections
  1. In 30 seconds
  2. Why this matters
  3. The college version
  4. Eli explains
  5. Worked example
  6. Key takeaway
  7. Check yourself
  8. Study tools
  9. Sources & references

In 30 seconds

Phenols react at two distinct sites: at the oxygen (after deprotonation to phenoxide, a powerful nucleophile) and at the ring (an activated aromatic system that undergoes electrophilic substitution easily). The oxygen chemistry gives ethers and esters — including the reaction that makes aspirin. The ring chemistry gives halogenated, nitrated, and carboxylated phenols — including the industrial route to salicylic acid (Kolbe–Schmitt). Phenols are also easily oxidized to quinones, a reaction with deep biological importance.

A useful mental map: (1) O–H reactivity — deprotonation, , ; (2) ring reactivity — at ortho/para; (3) oxidation — phenols ↔ quinones.

Why this matters

The reactions of phenols power several billion-dollar industries and central biological processes:

  • Aspirin is made by acetylating the phenolic –OH of salicylic acid — the most famous pharmaceutical reaction.
  • Aryl ethers made from phenoxides appear in drugs, fragrances, and polymers.
  • Kolbe–Schmitt carboxylation is the industrial route to salicylic acid, the aspirin precursor.
  • /hydroquinone redox couples power electron transport in mitochondria (coenzyme Q) and photosynthesis; vitamin K's blood-clotting function is quinone-based.
  • Phenol's easy bromination (no catalyst needed) is a classic demonstration of ring activation — a favorite exam topic.

The college version

Core Concepts

Deprotonation: making the phenoxide nucleophile

Phenol (pKa ≈ 10) is deprotonated by NaOH or NaH to give the :

C6H5OH + NaOH ⟶ C6H5O-Na+ + H2O

The phenoxide is a far better nucleophile than phenol itself (negative charge on oxygen, delocalized but available). Bicarbonate is too weak a base to do this (see Topic 9).

Williamson ether synthesis

Phenoxide + primary alkyl halide (or methyl/benzyl halide) → aryl alkyl ether via :

C6H5O- + CH3I ⟶ C6H5OCH3 + I-

Anisole (methoxybenzene) is made this way. Mechanism: the phenoxide oxygen attacks the back side of the carbon bearing the leaving group; the halide leaves; the C–O bond forms with inversion at carbon. Requirements: a good leaving group and an unhindered carbon — methyl and primary halides work well, secondary poorly, tertiary halides give elimination instead. Aryl halides (e.g., bromobenzene) cannot be used — SN2 does not occur at aromatic carbons, which is why you cannot make diphenyl ether by direct Williamson reaction.

Esterification: the aspirin reaction

Phenols react with acid chlorides or anhydrides (with pyridine or NaOH as base) to give phenyl esters:

C6H5OH + CH3COCl ⟶ C6H5OCOCH3 + HCl

Salicylic acid (o-hydroxybenzoic acid) has both a phenolic –OH and a –COOH. Acetylation with acetic anhydride converts only the phenolic –OH to an ester, giving — aspirin:

HOC6H4COOH + (CH3CO)2O ⟶ CH3COOC6H4COOH + CH3COOH

The –COOH is left free, which is essential because aspirin's anti-inflammatory activity depends on it.

Electrophilic aromatic substitution: the activated ring

The –OH group is a strong ortho/para director and ring activator. Phenol reacts with Br₂ in water even without a Lewis acid catalyst — three bromines add rapidly to give (a white solid):

C6H5OH + 3Br2 ⟶ Br3C6H2OH + 3HBr

Nitration with dilute nitric acid gives mostly p-nitrophenol (plus the ortho isomer); the isomers separate by steam distillation because the ortho isomer hydrogen-bonds intramolecularly and is more volatile. Compare with benzene, which needs fuming nitric acid, sulfuric acid, and heat — the –OH makes the ring dramatically more reactive.

Kolbe–Schmitt carboxylation

Heating sodium phenoxide with CO₂ under pressure, then acidifying, gives salicylic acid (ortho carboxylation):

C6H5O-Na+ + CO2 125 °C, pressure⟶ NaOOC–C6H4OH H3O+⟶ HOOC–C6H4OH

The phenoxide attacks the electrophilic carbon of CO₂, and the carboxylate lands ortho to the –OH. This is the industrial synthesis of salicylic acid.

Oxidation: phenols and quinones

Phenols are easily oxidized (they darken in air). With appropriate oxidants (e.g., Ag₂O, Na₂Cr₂O₇), hydroquinones give quinones:

HOC6H4OH [O]⟶ O=C6H4=O + 2H+ + 2e-

The hydroquinone/quinone pair is a reversible two-electron redox couple — the basis of coenzyme Q in the electron transport chain and of vitamin K's role in blood clotting. Hydroquinone and derivatives are also used as photographic developers and radical scavengers.

How It Works / Step-by-Step Process

Making an aryl alkyl ether (Williamson, general procedure):

  1. Deprotonate the phenol: C₆H₅OH + NaOH → C₆H₅O⁻Na⁺ (in water/ethanol), or use NaH in an aprotic solvent.
  2. Add the alkyl halide (methyl, primary, or benzyl — never tertiary): C₆H₅O⁻ attacks the carbon back side, halide leaves (SN2).
  3. Isolate: pour into water, extract with organic solvent, dry, remove solvent.
  4. Verify by spectroscopy: anisole shows aryl C–O (~1240 cm⁻¹ in IR) and a 3H singlet at ~3.8 ppm (OCH₃) in ¹H NMR.

Aspirin synthesis (educational outline, not a procedure to run without supervision):

  1. Warm salicylic acid with acetic anhydride and a catalytic amount of acid (e.g., phosphoric acid).
  2. The phenolic –OH is acetylated; the –COOH is not.
  3. Pour into cold water — aspirin precipitates; wash, recrystallize, dry.
  4. A negative confirms no free phenol remains.

Common Confusions

Do not confuseWithDifference
Williamson on phenolsAlkylation of the ringThe phenoxide oxygen alkylates (SN2, gives ethers); ring alkylation needs Friedel–Crafts-type conditions
Aryl halides in WilliamsonAlkyl halidesAr–X cannot do SN2 (aromatic carbons don't undergo back-side attack) — diphenyl ether cannot be made this way
3° alkyl halide in WilliamsonMethyl/1° halides3° halides undergo elimination (E2) with the basic phenoxide instead of substitution — no ether forms
Phenol + Br₂Benzene + Br₂Phenol reacts without catalyst (activated ring) to give 2,4,6-tribromophenol; benzene needs FeBr₃ and gives mono-bromobenzene
Oxidation of phenolsOxidation of alcoholsAlcohols → aldehydes/ketones/carboxylic acids; phenols → quinones (ring diones), a different redox system
Ester of phenolEster of carboxylic acidPhenyl esters (ArO–C(=O)R) form from phenols; carboxylate esters (R–O–C(=O)R′) form from alcohols/acids — different products
FeCl₃ positive testOnly phenolsEnols (e.g., 1,3-dicarbonyl tautomers) also give color — confirm with NMR/IR
Eli, the EliExplains learning guide

Eli explains

The same idea, in plain words

Explain it like I’m 10

Phenol is a ring with an –OH handle that can "let go" of its hydrogen to become a negative ion — a grabby helper that can snap new pieces (like a methyl group or a CO₂ molecule) into place. The ring itself is also super-eager to catch bromine and other electrophiles without needing a catalyst. That's why phenol builds aspirin, antiseptics, and plastics — and why it turns into a yellow dye (quinone) when oxidized, like an apple browning in air.

Worked example

Example 1: Williamson stoichiometry — anisole from phenol

Problem: How many grams of anisole (C₆H₅OCH₃, molar mass 108.14 g/mol) can be made from 5.00 g of phenol (C₆H₅OH, molar mass 94.11 g/mol) if the yield is 85%?

Formula first: n = mM, then mproduct = n × Mproduct × yield fraction.

n(phenol) = 5.00 g94.11 g/mol = 5.31 × 10-2 mol

The reaction is 1:1 (one phenol → one anisole), so:

mtheoretical = (5.31 × 10-2 mol)(108.14 g/mol) = 5.75 g

mactual = 5.75 g × 0.85 = 4.89 g

Dimensional analysis (one chain):

5.00 g phenol × 1 mol phenol94.11 g phenol × 1 mol anisole1 mol phenol × 108.14 g anisole1 mol anisole × 0.85 = 4.89 g anisole

Example 2: Predicting bromination products

Problem: Predict the product when p-cresol (4-methylphenol) is treated with excess Br₂ in water.

Analysis: The –OH is a strong ortho/para director. In 4-methylphenol, the para position is already occupied by –CH₃, so electrophilic bromination occurs at the two ortho positions (carbons 2 and 6, equivalent by symmetry).

Answer: 2,6-dibromo-4-methylphenol. The methyl group also directs ortho/para, but the –OH dominates; the product still has an intact –OH, confirmed by the FeCl₃ test and a broad IR O–H stretch near 3200–3600 cm⁻¹.

Example 3: Acid–base separation logic with phenoxides

Problem: A mixture of phenol (pKa 10.0), p-nitrophenol (pKa 7.2), and anisole (no acidic proton) is dissolved in ether. Which compound is extracted into aqueous NaHCO₃? Into aqueous NaOH?

Analysis: NaHCO₃ (conjugate acid H₂CO₃, pKa 6.35) deprotonates only acids stronger than carbonic acid: p-nitrophenol (7.2) partially; phenol (10.0) not at all; anisole not at all. NaOH (conjugate acid H₂O, pKa 15.7) deprotonates both phenols fully. So NaOH extracts p-nitrophenol + phenol; NaHCO₃ extracts only the strongest acid (mostly); anisole stays in ether throughout.

Key takeaways

  • Phenoxide (from NaOH) is the reactive nucleophile; it alkylates methyl/primary/benzyl halides (Williamson) — never aryl halides.
  • Aspirin = acetylation of salicylic acid's phenolic –OH with acetic anhydride; the –COOH stays free.
  • Phenol is so activated that Br₂/H₂O gives 2,4,6-tribromophenol with no catalyst; benzene needs FeBr₃ + Br₂.
  • –OH directs electrophiles ortho/para; nitro groups deactivate but o/p mixtures still form.
  • Kolbe–Schmitt: phenoxide + CO₂ (heat, pressure) → salicylic acid after acidification — industrial aspirin feedstock.
  • Phenols oxidize to quinones; hydroquinone ⇌ quinone is a reversible redox couple (biology: coenzyme Q, vitamin K).
  • FeCl₃ gives a violet color with phenols (enols too) — quick qualitative test.
  • Safety principle: phenols are corrosive and can be toxic; work with gloves in a ventilated area and avoid skin contact.

Check yourself

6 review questions from the chapter. Try each one, then open the answer.

  1. Write the two-step sequence (reagents) to convert phenol to anisole, and name the mechanism of the key step.

    Show answer

    (1) C₆H₅OH + NaOH → C₆H₅O⁻Na⁺; (2) C₆H₅O⁻ + CH₃I → C₆H₅OCH₃ + NaI. The key step is SN2 — phenoxide attacks methyl iodide's carbon from the back side.

  2. Why can't you make diphenyl ether by reacting phenoxide with bromobenzene?

    Show answer

    Bromobenzene's aromatic carbon cannot undergo SN2: the back-side attack required would have to occur on an sp² carbon inside the ring, which is geometrically impossible and electronically unfavorable. Aryl ethers need different methods (e.g., copper-mediated coupling or SNAr with strong EWG).

  3. Which functional group of salicylic acid is acetylated in aspirin synthesis, and why does the –COOH stay free?

    Show answer

    Only the phenolic –OH is acetylated (acetic anhydride). The –COOH is too unreactive toward acylation under these conditions, and keeping it free is essential for aspirin's pharmacological activity.

  4. Explain why phenol reacts with Br₂ in water without a catalyst while benzene requires FeBr₃.

    Show answer

    The –OH donates electron density into the ring (resonance + induction), raising electron density at ortho/para carbons so they attack the electrophile (Br⁺) without needing a Lewis acid to generate it. Benzene's ring is far less electron-rich.

  5. What is the , and why is it industrially important?

    Show answer

    Sodium phenoxide + CO₂ under heat/pressure gives the ortho-carboxylate; acidification gives salicylic acid — the industrial route to the aspirin precursor.

  6. Give one biological example of a quinone/hydroquinone redox system.

    Show answer

    Coenzyme Q (ubiquinone/ubiquinol) shuttles electrons in the mitochondrial electron transport chain; vitamin K (a quinone) participates in blood-clotting factor carboxylation; hydroquinone is also used industrially as a developer/scavenger.

Keep learning

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Study tools & related lessonsKey vocabulary · Related

Key vocabulary

phenoxide ion
Conjugate base of phenol (C₆H₅O⁻)
Williamson ether synthesis
SN2 alkylation of an alkoxide/phenoxide by an alkyl halide
SN2
One-step substitution: nucleophile attacks as leaving group departs
esterification
Reaction of an alcohol/phenol with an acid chloride or anhydride
acetylsalicylic acid
Aspirin: salicylic acid with the phenolic –OH acetylated
electrophilic aromatic substitution (EAS)
Replacing an aromatic H with an electrophile
2,4,6-tribromophenol
Triple bromination product of phenol
Kolbe–Schmitt reaction
Phenoxide + CO₂ → ortho-hydroxybenzoate → salicylic acid
quinone
Cyclic dione from oxidation of a hydroquinone
FeCl₃ test
Iron(III) chloride color test for phenols/enols

Sources & references

  1. openstax.org — Organic Chemistry

This lesson was adapted from the open educational references above; their licenses and attributions are preserved. See Copyright & Licensing.

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