DAT Review · Quantitative Reasoning
Algebra
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In 30 seconds
Algebra is the backbone of the DAT Quantitative Reasoning section. Of the 40 QR questions (45 minutes, on-screen basic calculator provided), approximately 8-12 directly test algebraic manipulation. But algebra skills also underpin word problems, quantitative comparison, and even some geometry questions. You cannot score well on QR without fluent algebra.
The DAT algebra questions span: simplifying expressions, solving linear equations and systems, inequalities, absolute value equations, exponent and radical rules, quadratic equations, and function notation. The difficulty is roughly precalculus level — nothing beyond Algebra II, but with time pressure that demands automaticity.
The college version
Strategy/Review
Simplifying Expressions
The core skill: combine like terms systematically. Work left to right, grouping terms with the same variable and exponent.
Example: Simplify 3x² + 5x − 2x² + 7x − 4 → Group x² terms: 3x² − 2x² = x² → Group x terms: 5x + 7x = 12x → Constants: −4 → Result: x² + 12x − 4
Fast rearrangement technique: When an expression is messy, circle each "chunk" (each term with its sign) and rearrange mentally before writing.
Solving Linear Equations
The golden rule: whatever you do to one side, do to the other. Your goal is to isolate the variable.
Standard approach:
- Clear parentheses (distribute).
- Combine like terms on each side.
- Move variable terms to one side, constants to the other.
- Divide by the coefficient.
Example: 3(x − 4) + 2x = 5x − 8 → 3x − 12 + 2x = 5x − 8 → 5x − 12 = 5x − 8 → −12 = −8 ❌ No solution (contradiction). The DAT sometimes includes equations with no solution or infinite solutions — recognize these quickly.
Systems of Equations
Two methods, choose based on the equation structure:
Substitution: Best when one variable is already isolated or easy to isolate. → Solve one equation for x (or y). → Substitute that expression into the other equation. → Solve for the remaining variable. → Back-substitute to find the other.
Elimination: Best when coefficients line up nicely. → Multiply one or both equations so the coefficients of one variable are opposites. → Add the equations to eliminate that variable. → Solve for the remaining variable. → Back-substitute.
Example — Elimination: 2x + 3y = 12 4x − 3y = 6 → Add: 6x = 18 → x = 3 → Substitute: 2(3) + 3y = 12 → 6 + 3y = 12 → 3y = 6 → y = 2 → Solution: (3, 2)
Inequalities
Same rules as equations with ONE critical exception: multiplying or dividing by a NEGATIVE number FLIPS the inequality sign.
Example: −2x + 5 > 11 → −2x > 6 → x < −3 (divided by −2, flipped the sign)
Compound inequalities: −4 ≤ 2x + 1 < 7 → Subtract 1: −5 ≤ 2x < 6 → Divide by 2: −2.5 ≤ x < 3
Absolute Value Equations
The rule: |expression| = k means expression = k OR expression = −k. Always check BOTH cases.
Example: |2x − 3| = 7 → Case 1: 2x − 3 = 7 → 2x = 10 → x = 5 → Case 2: 2x − 3 = −7 → 2x = −4 → x = −2 → Solutions: x = 5 or x = −2
Absolute value inequalities (split into two): |x| < k → −k < x < k |x| > k → x < −k OR x > k
Exponent Rules (Must Be Automatic)
- xᵃ · xᵇ = xᵃ⁺ᵇ (multiplying same base → add exponents)
- xᵃ / xᵇ = xᵃ⁻ᵇ (dividing same base → subtract exponents)
- (xᵃ)ᵇ = xᵃᵇ (power to a power → multiply exponents)
- x⁰ = 1 (any nonzero base to the 0 power = 1)
- x⁻ᵃ = 1/xᵃ (negative exponent → reciprocal)
- x^(1/n) = ⁿ√x (fractional exponent → root)
- (xy)ᵃ = xᵃyᵃ (power of a product)
Radicals
Key simplification: √(x²) = |x| (the principal root is always nonnegative).
Operations:
- √a · √b = √(ab)
- √a / √b = √(a/b)
- To add/subtract radicals, they must have the same radicand: 2√3 + 5√3 = 7√3, but 2√3 + 5√2 cannot be combined.
Rationalizing denominators: Multiply numerator and denominator by the conjugate or the radical that clears the denominator.
Quadratics
Three solution methods, ordered by preference:
1. Factoring (fastest): If the quadratic factors nicely. x² + 5x + 6 = 0 → (x + 2)(x + 3) = 0 → x = −2 or x = −3
2. Quadratic formula (always works): x = [−b ± √(b² − 4ac)] / 2a Use the discriminant (b² − 4ac) to predict:
- If > 0: two real solutions
- If = 0: one real solution (double root)
- If < 0: no real solutions (complex)
3. Completing the square: Useful when the quadratic is almost a perfect square, or when the answer choices are in vertex form.
Common Traps
Trap 1 — Inequality Sign Forgetfulness. The single most common QR algebra error: dividing by a negative without flipping the sign. Every time you divide or multiply by a negative in an inequality, pause and verify the sign direction.
Trap 2 — Distributing Minus Signs Incorrectly. −(3x − 4) = −3x + 4, not −3x − 4. The minus sign distributes to EVERY term inside the parentheses.
Trap 3 — Extraneous Solutions from Squaring. When you square both sides of an equation (common with radical equations), you may introduce extraneous solutions. Always plug answers back into the original equation.
Trap 4 — Forgetting ± in Square Roots. x² = 16 means x = ±4. The equation has two solutions, even though √16 = 4 (just the principal root). Don't confuse solving x² = k (two solutions) with evaluating √k (one, nonnegative).
Trap 5 — Canceling Terms Instead of Factors. You can cancel FACTORS (things being multiplied), but NOT TERMS (things being added/subtracted). (x² + 3x)/x = x + 3 (cancel factor x). But (x + 3)/x does NOT simplify to 3 — you cannot cancel the x terms.

Eli explains
The same idea, in plain words
Explain it like I’m 10
Algebra is like being a reverse detective. Someone hands you a puzzle like "3 times a mystery number plus 4 equals 19" and you have to figure out the mystery number.
Your tools:
- You can add, subtract, multiply, or divide — AS LONG AS you do it to BOTH sides of the equation (like keeping a seesaw balanced).
- Your goal is always the same: get the mystery letter (usually x) alone on one side.
The biggest gotcha: inequality signs (<, >). If you multiply or divide by a NEGATIVE number, the sign FLIPS. < becomes > and vice versa. It's the "UNO reverse card" of algebra.
For quadratics (equations with x²), you usually get TWO answers, not just one. That's because both 3² and (−3)² equal 9 — so x² = 9 means x could be 3 or −3.
Key takeaways
- Solve: 2(x − 3) + 4x = 3(2x + 1) − 5. (Answer: 6x − 6 = 6x + 3 − 5 → 6x − 6 = 6x − 2 → −6 = −2 → No solution.)
- Solve the system: 3x + 2y = 8, 5x − 2y = 0. (Answer: Add → 8x = 8 → x = 1, then 3(1) + 2y = 8 → y = 2.5.)
- Solve: |x + 4| > 6. (Answer: x + 4 < −6 OR x + 4 > 6 → x < −10 OR x > 2.)
- Factor: 2x² − 7x − 15 = 0. (Answer: (2x + 3)(x − 5) = 0 → x = −3/2 or x = 5.)
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