DAT Review · Quantitative Reasoning

Word Problems

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  1. In 30 seconds
  2. The college version
  3. Eli explains
  4. Key takeaway
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In 30 seconds

Word problems are the most heavily tested category in DAT Quantitative Reasoning, appearing in roughly 12-16 of the 40 QR questions. They're also the most feared — not because the underlying math is hard, but because translation from English to equations is a skill that must be deliberately practiced. The DAT tests seven major word problem archetypes: distance/rate/time, work/rate, mixtures, age problems, interest, consecutive integers, and ratio/proportion scenarios.

The good news: word problems are formulaic. Once you recognize the archetype, you apply a template. The hard part is the recognition. This guide gives you the templates AND the recognition cues.

The college version

Strategy/Review

The Translation Method: English → Variables → Equation → Solve

This four-step pipeline turns any word problem into solvable math:

Step 1 — English: Read the problem. Identify what's being asked. Let that unknown be your variable (usually x).

Step 2 — Variables: Express all other quantities in terms of x using the relationships stated in the problem. "Three more than twice a number" → 2x + 3. "Five years ago" → x − 5.

Step 3 — Equation: Find the sentence that states an equality. "The sum is 42" → build your equation. "They arrive at the same time" → set times equal.

Step 4 — Solve: Use algebra. Check that your answer makes sense in the original context (no negative ages, no speeds exceeding the speed of light).

Archetype 1: Distance = Rate × Time

Formula: d = r × t → r = d/t → t = d/r

This is the most versatile QR formula. Every distance/rate/time problem uses it, often in multi-step scenarios.

Example — Opposite directions: Two cars start 300 miles apart and drive toward each other. Car A goes 60 mph, Car B goes 40 mph. When do they meet? → Combined rate = 60 + 40 = 100 mph → Time = distance / rate = 300 / 100 = 3 hours

Example — Catch-up: Car A leaves at 50 mph. Car B leaves 2 hours later at 70 mph. When does B catch A? → In 2 hours, A travels 100 miles (head start). → B gains 20 mph on A (relative speed: 70 − 50). → Time to close 100 miles at 20 mph = 5 hours after B departs.

Example — Round trip: A plane flies 600 miles at 300 mph with the wind and returns at 200 mph against the wind. What's the average speed? → NOT (300 + 200)/2 = 250 mph! → Time out = 600/300 = 2 hours. Time back = 600/200 = 3 hours. → Total distance = 1200 miles. Total time = 5 hours. → Average speed = 1200/5 = 240 mph.

Archetype 2: Work/Rate Problems

Formula: 1/t₁ + 1/t₂ + ... + 1/tₙ = 1/T Where t₁, t₂, ... are individual times to complete the job alone, and T is the time to complete it together.

Intuition: Each person contributes a RATE (what fraction of the job they complete per unit time). Rates add. 1/t is the rate (jobs per hour).

Example: Alice can paint a room in 4 hours. Bob can paint it in 6 hours. How long together? → Rate of Alice = 1/4 room/hr. Rate of Bob = 1/6 room/hr. → Combined rate = 1/4 + 1/6 = 3/12 + 2/12 = 5/12 room/hr. → Time = 1 / (5/12) = 12/5 = 2.4 hours (or 2 hours 24 minutes).

Example — One helps then leaves: Alice works alone for 1 hour (completes 1/4 of the room). Bob joins. How much longer? → Remaining: 3/4 of the room. → Combined rate: 5/12 room/hr. → Time = (3/4) / (5/12) = (3/4) × (12/5) = 9/5 = 1.8 hours more.

Archetype 3: Mixture Problems

Formula: C₁V₁ + C₂V₂ = C_total × V_total Where C = concentration (or price, or percent) and V = volume (or quantity, or weight).

Example: How much pure alcohol (100%) must be added to 500 mL of a 20% solution to make a 50% solution? → Let x = mL pure alcohol added. → (1.00)(x) + (0.20)(500) = (0.50)(500 + x) → x + 100 = 250 + 0.5x → 0.5x = 150 → x = 300 mL

Example — Pricing: How many pounds of $4/lb coffee must be mixed with 10 pounds of $7/lb coffee to make a blend worth $5/lb? → 4x + 7(10) = 5(x + 10) → 4x + 70 = 5x + 50 → x = 20 pounds

Archetype 4: Age Problems

Strategy: Use a table or timeline. "Now" is your baseline. x = current age of the person the question asks about.

Example: John is twice as old as Mary. In 10 years, John will be 5 years older than Mary. Find John's current age. → Now: John = 2x, Mary = x → In 10 years: John = 2x + 10, Mary = x + 10 → Equation: 2x + 10 = (x + 10) + 5 → 2x + 10 = x + 15 → x = 5 → John is 10.

Trick: This problem's equation simplifies to x = 5 regardless of the number of years — the age difference is always constant! 2x − x = (2x+10) − (x+10) − 5 → x = 5.

Archetype 5: Simple Interest

Formula: I = P × r × t Where I = interest, P = principal, r = annual interest rate (as decimal), t = time in years.

Example: $5,000 invested at 4% simple interest for 3 years. Total interest? → I = 5000 × 0.04 × 3 = $600.

Total amount: A = P + I = P(1 + rt)

Compound interest (if tested): A = P(1 + r/n)^(nt) Where n = compounding periods per year. The DAT rarely requires compound interest calculations (they're calculator-intensive), but you may need to recognize the formula or compare simple vs. compound conceptually.

Archetype 6: Consecutive Integers

Consecutive integers: x, x+1, x+2, ... Consecutive even/odd: x, x+2, x+4, ... (start with an even x for evens, odd x for odds)

Example: The sum of three consecutive odd integers is 63. Find the smallest. → x + (x+2) + (x+4) = 63 → 3x + 6 = 63 → 3x = 57 → x = 19 → Integers: 19, 21, 23.

Archetype 7: Ratio and Proportion Word Problems

Example: The ratio of boys to girls in a class is 3:4. If there are 28 students, how many boys? → Let boys = 3k, girls = 4k. → 3k + 4k = 28 → 7k = 28 → k = 4 → Boys = 3(4) = 12.

Common Traps

Trap 1 — Average Speed ≠ Average of Speeds. Average speed = total distance / total time, NOT (speed1 + speed2)/2. The round-trip plane example above demonstrates this.

Trap 2 — Work Rates: Forgetting to Use Reciprocals. "Alice does the job in 4 hours" means her rate is 1/4. The most common error is writing "4" instead of "1/4" in the rate equation.

Trap 3 — Mixture: Forgetting Total Volume Changes. When you add pure alcohol, the total volume increases. The denominator in the final concentration is (original volume + added volume), not just the original.

Trap 4 — Age: Not Accounting for Everyone Aging. If a problem says "in 10 years," ALL people age 10 years. A student might add 10 to one person's age but forget the other.

Trap 5 — Interest: Confusing Simple and Compound. Simple interest = interest on principal only. Compound = interest on principal + accumulated interest. Compound grows faster.

Eli, the EliExplains learning guide

Eli explains

The same idea, in plain words

Explain it like I’m 10

Word problems seem scary because they hide math inside a story. But every word problem follows a recipe. Here's how to crack them:

  1. Find the question. What do they want you to figure out? That's your "x."
  2. Translate the story into math. "Five more than twice a number" = 2x + 5. "The product of" = multiply. "Sum" = add. "Difference" = subtract.
  3. Find the equals sign hidden in the words. "Is," "was," "results in," "equals," "the same as" — these all mean "=."
  4. Solve like normal algebra.
  5. Check: Does your answer make sense in the story? (No negative ages. No cars going 900 mph.)

The seven types of word problems on the DAT:

  • Distance: Speed × Time = Distance. Draw a picture!
  • Work: How fast people work together. Use 1/time fractions.
  • Mixtures: Mixing stuff. Use the concentration equation.
  • Age: Draw a timeline for "now" and "then."
  • Interest: Money growing. Principal × Rate × Time.
  • Consecutive numbers: Numbers in a row. x, x+1, x+2.
  • Ratios: Comparing amounts. Use k as the multiplier.

Key takeaways

  • Two pipes fill a tank. Pipe A takes 3 hours alone, Pipe B takes 6 hours alone. With both open, how long? (Answer: 1/3 + 1/6 = 1/2 tank/hr → 2 hours.)
  • A car travels 40 miles at 20 mph, then 40 miles at 40 mph. Average speed? (Answer: Time1 = 2 hrs, Time2 = 1 hr. Total = 80 miles / 3 hours = 26.67 mph, NOT 30 mph.)
  • How much water must be added to 300 mL of 80% acid to make a 50% acid solution? (Answer: 0.80(300) + 0(x) = 0.50(300 + x) → 240 = 150 + 0.5x → x = 180 mL.)
  • Tom is 4 years older than Jerry. In 3 years, Tom will be twice as old as Jerry. Find Tom's current age. (Answer: Tom = x, Jerry = x−4. (x+3) = 2(x−4+3) → x+3 = 2x−2 → x = 5. Tom is 5.)

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