Organic Chemistry · Reactions of Alkyl Halides: Nucleophilic Substitutions and Eliminations
Biological Elimination Reactions
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In 30 seconds
Enzymes perform the same elimination chemistry as alkyl halides — removing a β-hydrogen and a leaving group from adjacent carbons to make an alkene — under conditions that would stop a laboratory reaction: water, pH near 7, 37 °C. Cells solve this in three ways: general bases (histidine, glutamate, or aspartate side chains) replace free strong bases; poor leaving groups (hydroxide, phosphate, ammonia) are activated by protonation or metal-ion coordination; carbanion intermediates are stabilized by electron-withdrawing groups, hydrogen bonding, metal ions, and cofactors such as PLP. Most biological eliminations are therefore E1cB-like.
Why this matters
Biological eliminations sit at the heart of central metabolism: enolase dehydrates 2-phosphoglycerate to phosphoenolpyruvate (PEP) in glycolysis; fumarase dehydrates malate to fumarate in the citric acid cycle; aconitase dehydrates and rehydrates citrate en route to isocitrate; histidine ammonia-lyase removes ammonia from histidine; PLP-dependent enzymes such as serine dehydratase convert amino acids into keto acids. Understanding why the enzyme protonates the leaving group, needs a metal ion, and is stereospecific explains inhibition and metabolic disorders — the alkyl-halide E1cB framework governs biochemistry.
The college version
Core Concepts
What enzymes cannot do — and what they do instead
At physiological pH there is no free hydroxide or alkoxide; a strong base would attack everything. Enzymes instead use general base catalysis An enzyme side chain (His, Glu, Asp) removes a proton, often through a relay Full entry →: a side chain (e.g., histidine's imidazole) removes the β-hydrogen, accepting the proton into a relay. general acid catalysis An enzyme side chain donates a proton to activate a leaving group Full entry → or a metal ion (Mg²⁺, Zn²⁺, Fe–S) activates the leaving group: a protonated hydroxyl is water — an excellent leaving group. The enzyme makes the leaving group better, the β-H more acidic, and the intermediate more stable, all at once: a "push–pull" design, the enzymatic version of E1cB.
The E1cB logic: stabilize the carbanion first
Enzymatic eliminations usually begin by deprotonating a β-hydrogen made acidic by an adjacent electron-withdrawing group. In carbonyl chemistry this is the α-position: deprotonation gives an enolate A carbanion adjacent to a carbonyl, stabilized by resonance Full entry →, its negative charge delocalized onto oxygen. Enzymes stabilize enolates by hydrogen-bonding the developing oxyanion and coordinating metal ions, lowering the α-H pKa from ~19–20 to a value a neutral base can reach. Only then does the leaving group depart. Because deprotonation is usually the slow step, a primary deuterium isotope effect — the same fingerprint as E2 — identifies the rate-determining step.
Poor leaving groups and their activation
Biology's leaving groups are mostly poor by laboratory standards: hydroxide, alkoxide, phosphate, pyrophosphate, ammonia (as NH₄⁺), even carboxylates. Each is activated characteristically: OH is protonated to water (enolase, fumarase, aconitase); phosphate/pyrophosphate leave as stable anions assisted by Mg²⁺; NH₃ from an α-amino group departs after the β-H is removed, with the C–N electrons forming an imine — PLP or an electrophilic cofactor (MIO An electrophilic cofactor in histidine/phenylalanine ammonia-lyases Full entry → in histidine and phenylalanine ammonia-lyases) makes the β-H acidic enough to start.
Cofactors extend the chemistry
pyridoxal phosphate (PLP) A cofactor that forms imines with amino acids, making α-H acidic Full entry → is the workhorse of amino-acid eliminations. PLP forms a Schiff base (imine) with the amino acid; the imine is an electron sink that lowers the pKa of the α-hydrogen from ~30 toward 7, so a general base can remove it. The resulting carbanion eliminates the β-substituent (OH, OR, or another group); the imine hydrolyzes to the keto acid and ammonia. Serine dehydratase, threonine dehydratase, and cystathionine β-lyase all work this way.
Stereospecificity
Enzymatic eliminations are often anti and stereospecific: the enzyme removes a specific hydrogen (one prochiral face) and the leaving group from the opposite face, giving one alkene geometry. Fumarase dehydrates L-malate to trans-fumarate with complete control, removing the pro-R hydrogen — the biological echo of E2's anti-periplanar requirement.
How It Works / Step-by-Step Process
- Identify what will be lost: a β-H and a leaving group (OH, phosphate, NH₃, OR).
- Find how the leaving group is activated: protonation, metal coordination, or a stable anion.
- Find what makes the β-H acidic: a carbonyl, imine (PLP), or electrophilic cofactor (MIO).
- Deprotonate first (E1cB) to form the stabilized enolate; watch for a primary KIE.
- Eject the leaving group, form the alkene, note stereochemistry.
Worked Example: Enolase — Dehydration to Phosphoenolpyruvate
In glycolysis, enolase converts 2-phosphoglycerate (2-PG) to phosphoenolpyruvate (PEP), the pathway's highest-energy phosphate:
2-phosphoglycerate enolase⟶ phosphoenolpyruvate + H2O
In structure terms, 2-PG is HOOC-CH(OPO32-)-CH2OH; PEP is HOOC-C(OPO32-)=CH2. A glutamate side chain (general base) removes the proton from C2 — α to the carboxylate — forming a carbanion/enolate stabilized by two Mg²⁺ ions coordinated to the carboxylate and phosphate. The β-hydroxyl at C3 leaves as water (assisted by Mg²⁺ and protonation), and C2–C3 becomes a double bond: E1cB in action.
Worked Example: Fumarase — a Stereospecific Anti Dehydration
In the citric acid cycle, fumarase dehydrates L-malate to fumarate:
HOOC-CH(OH)-CH2-COOH fumarase⟶ HOOC-CH=CH-COOH + H2O
The reaction is stereospecific: fumarase removes the pro-R hydrogen of the methylene carbon and the hydroxyl from the opposite face (anti elimination Loss of β-H and LG from opposite C–C faces Full entry →), giving exclusively the trans alkene, fumarate — never maleate. An aspartate side chain is the general base, and the hydroxyl leaves as water after protonation — E1cB deprotonation, poor-LG activation (OH → H₂O), and anti, stereospecific alkene formation.
Worked Example: Histidine Ammonia-Lyase — Losing Ammonia
Histidine ammonia-lyase (histidase) eliminates ammonia from L-histidine, giving urocanate in histidine catabolism:
L-histidine histidase⟶ urocanate + NH3
The amino group is the leaving group — very poor in the flask — and the β-hydrogen sits on a non-acidic carbon. The enzyme's electrophilic cofactor MIO reacts with the substrate to make the β-H acidic; a general base removes it, and the C–N electrons form the double bond as ammonia departs, giving the trans alkene. (MIO details are still studied; the E1cB framework is the standard model.)
Common Confusions
| Do not confuse | With | Difference |
|---|---|---|
| Biological eliminations = E2 with strong base | E1cB-like mechanisms | Cells have no free strong bases; they use general bases and stabilize carbanions |
| “Poor leaving groups can't leave in biology” | Activation of leaving groups | Enzymes protonate OH to H₂O or coordinate phosphates to Mg²⁺ so they can leave |
| Dehydration always means alcohol → alkene | Biological dehydrations | Enzymes also dehydrate carboxylates (malate → fumarate) |
| PLP is only for transamination | PLP in eliminations | PLP also catalyzes β-eliminations (serine dehydratase) by making the α-H acidic |
| Enzymes are not stereospecific | Enzymatic eliminations | They often are — fumarase makes only trans-fumarate |
| Primary KIE = proof of E2 specifically | KIE meaning | It proves the C–H bond breaks in the slow step — consistent with E2 and E1cB |

Eli explains
The same idea, in plain words
Explain it like I’m 10
Your cells can't use strong chemical cleaners, so enzymes act like careful crafters: one part holds the molecule, another gently pulls a hydrogen off, and another helps the "handle" (water or ammonia) fall off — in the right order and direction. It's the lab's un-zipping trick, done with tiny, precise tools.
Key takeaways
- Biological eliminations are E1cB-like: deprotonate the activated β-H first, then eject the leaving group.
- Enzymes use general bases (His, Glu, Asp), not free hydroxide, plus general acids/metal ions to activate leaving groups.
- Poor biological leaving groups (OH, phosphate, NH₃) are activated by protonation, metal coordination, or stable-anion formation.
- Enolates are the key intermediates; H-bonding and metal ions lower the α-H pKa toward neutral.
- Rate-determining deprotonation gives a primary KIE on the β-H — the same logic as E2.
- Key examples: enolase (2-PG → PEP), fumarase (malate → fumarate), aconitase (citrate ⇌ isocitrate), histidine ammonia-lyase, PLP dehydratases.
- Enzymatic eliminations are often anti and stereospecific (fumarase makes only trans-fumarate).
Check yourself
6 review questions from the chapter. Try each one, then open the answer.
Why can't enzymes simply use hydroxide or alkoxide as bases?
Show answer
Free hydroxide/alkoxide are absent at physiological pH, and a strong base would attack many substrates; enzymes use general bases instead.
What are the three general strategies enzymes use to make eliminations possible?
Show answer
General base catalysis to remove the β-H; activation of the leaving group (protonation, metal coordination, stable anion); stabilization of the enolate (H-bonding, metal ions, cofactors).
Why is the enolate intermediate so important in biological eliminations?
Show answer
The enolate is the E1cB intermediate; resonance lowers the β-H pKa so a neutral base can remove it, and it stores the electrons that expel the leaving group.
What role does a metal ion such as Mg²⁺ play in enolase?
Show answer
Mg²⁺ coordinates the carboxylate and phosphate of 2-phosphoglycerate, stabilizing the enolate and assisting the β-hydroxyl's departure as water.
How does PLP make the β-elimination of serine possible?
Show answer
PLP forms a Schiff base with serine; the imine electron sink lowers the α-H pKa, a base removes it, the β-hydroxyl leaves, and the product gives pyruvate and ammonia.
What does a primary KIE tell a biochemist about an enzyme's elimination mechanism?
Show answer
A primary KIE (kH/kD ≈ 5--10) shows the C–H bond breaks in the rate-determining step — deprotonation is slow, so the mechanism is E1cB-like.
Study tools & related lessonsKey vocabulary · Related
Key vocabulary
- general base catalysis
- An enzyme side chain (His, Glu, Asp) removes a proton, often through a relay
- general acid catalysis
- An enzyme side chain donates a proton to activate a leaving group
- enolate
- A carbanion adjacent to a carbonyl, stabilized by resonance
- pyridoxal phosphate (PLP)
- A cofactor that forms imines with amino acids, making α-H acidic
- MIO
- An electrophilic cofactor in histidine/phenylalanine ammonia-lyases
- anti elimination
- Loss of β-H and LG from opposite C–C faces
- primary kinetic isotope effect
- kH/kD ≈ 5--10 when the labeled C–H bond breaks in the slow step
Sources & references
This lesson was adapted from the open educational references above; their licenses and attributions are preserved. See Copyright & Licensing.
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